Answer:
The acceleration of the bucket is 3.77m / S ^ 2 up
Explanation:
Hello,
To solve this exercise we must initially draw the free-body diagram (see attached image) of the bucket, and identify the forces present in this case would be the tension force of the rope and the weight of the bucket.
Then use Newton's law that states that the sum of the forces in a body is equal to mass per accession. We will assume that up is positive and down is negative
T=tension=163N
m=mass of bucket =12kg
g=gravity=9.81m/S^2
T-mg=m(a)
[tex]\frac{T-mg}{m} =a\\\frac{163N-(12kg)(9.81m/S^2}{12}=3.77m/s^2[/tex]
The acceleration of the bucket is 3.77m / S ^ 2 up