Question

Two squares overlap. The area of the overlapped region is 1/4 of the small squares area and is 2/9 of the large square area. What is the ratio of the area of the small square to the large square?

Answer 1

Answer:

ratio is 8 is to 9

Step-by-step explanation:

Let small square area be S, and

Large square area be L

We can come up with 2 equations and equate them to find the RATIO.

First, Area of Overlap is 1/4th of small square area. We can write:

A = 1/4*S  [A is area of overlapped region]

Second, Area of Overlap is 2/9th of Large square area. We can write:

A = 2/9*L  [A is area of overlapped region]

Let's equate both A's to get:

$\frac{1}{4}S=\frac{2}{9}L$

We need ratio of S to L, thus we can rearrange, cross multiply and rearrange to find the ratio of S to L. Shown below:

$\frac{1}{4}S=\frac{2}{9}L\\\frac{S}{4}=\frac{2L}{9}\\9S=8L\\\frac{9S}{L}=\frac{8L}{L}\\\frac{9S}{L}=8\\\frac{S}{L}=\frac{8}{9}$

Thus the ratio is 8 is to 9