Question

Debbie is making an abstract painting with two triangles. The dimensions of the painting are shown below:

Two triangles share the same height of 8 inches. One triangle has a base of 6 inches and the other is 10 inches.

The total area of the two triangles is _____ square inches.

Answer 1

The surface of the triangle count formula
A = b*h*1/2
A - area
b - base
c - height
The first triangle
A₁ = b₁*h = 6in * 8in *1/2= 24in²

The second triangle
A₂ b₂*h = 10in * 8in*1/2 = 40in²

The total area of the two triangles is 24in² + 40in² = 64 square inches

Answer 2

Debbie's abstract painting are two in numbers both having the same height. since we know the area of a triangle to be

Area = 1/2*Base*Height

Total area =Area of  Triangle A+ Area of  Triangle B

= 24+40

=64 square inches

Given data

Both Triangles share the same height = 8 inches

For Triangle A

Base = 6 inches

Area = 1/2 Base*Height

Area = 1/2*8*6

Area = 24 square inches

For Triangle B

Base = 10 inches

Area = 1/2 Base*Height

Area = 1/2*8*10

Area = 40 square inches

Total = 24+40

Total = 64 square inches

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