Question

Write a balanced half-reaction describing the reduction of aqueous iron(III) cations to aqueous iron(II) cations.​

Answer 1

Answer: The balanced half reaction is written below.

Explanation:

Reduction reaction is defined as the chemical reaction in which an atom gains electrons. The oxidation number of the atom gets reduced during this reaction.

$X^{n+}+ne^-\rightarrow X$

When iron (III) cations is reduced to iron (II) cations, the number of electron transfer is 1.

The chemical equation for the reduction of iron (III) cations follows:

$Fe^{3+}(aq.)+e^-\rightarrow Fe^{2+}(aq.)$

Hence, the balanced half reaction is written above.

Answer 2

The reaction for the reduction of aqueous iron(III) cations to aqueous iron(II) cations is Fe^3+(aq) + e -----> Fe^2+(aq)

The conversion from iron(III)  to  iron(II) is a reduction reaction. A reaction reaction occurs when a chemical specie gains electrons and undergoes a decrease in oxidation number.

The following equation describes the reduction of iron(III)  to  iron(II);

Fe^3+(aq) + e -----> Fe^2+(aq). We can see that iron(III)  is converted to  iron(II) by gaining one electron.

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