Question

You place a box weighing 289.9 N on an inclined plane that makes a 35.9 degree angle with the horizontal. Compute the component of the gravitational force acting down the inclined plane. Answer in units of N

Answer 1

Answer:

Fgparallel =  170N

Explanation:

Acting down the incline would be the paralell force. The Force of gravity on an incline for the parallel portion is mgsinθ.

Fg parallel = mgsinθ

mg is 289.9, as that is the weight. θ is 35.9

Fgpar = 289.9sin35.9

Fgparallel =  170N