He has 20 pennies, 8 nickels and 5 dimes
Step-by-step explanation:
Lets revise the values of the coins with respect to the cent
1. 1 nickel = 5 cents
2. 1 dime = 10 cents
3. 1 penny = 1 cent
Assume that:
The number of pennies is p
The number of nickels is n
The number of dimes is d
∵ Tony has 110 cents in nickels, dimes, and pennies
∴ p + 5n + 10d = 110 ⇒ (1)
∵ He has 3 more nickels than dimes
∴ n = d + 3 ⇒ (2)
∵ He has 4 times as many pennies as dimes
∴ p = 4d ⇒ (3)
- Substitute equations (2) and (3) in equation (1)
∴ 4d + 5(d + 3) + 10d = 110
∴ 4d + 5d + 15 + 10d = 110
- Add like terms in the left hand side
∴ 19d + 15 = 110
- Subtract 15 from both sides
∴ 19d = 95
- Divide both sides by 19
∴ d = 5
- Substitute the value of d in equations (2) and (3)
∵ n = d + 3
∵ d = 5
∴ n = 5 + 3
∴ n = 8
∵ p = 4d
∵ d = 5
∴ p = 4(5)
∴ p = 20
He has 20 pennies, 8 nickels and 5 dimes
Learn more:
You can learn more about solving equations in brainly.com/question/13168205
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