Question

PLEASE HELP!

Find the value of k so that the point A (5, 6) belongs to the graph of the following equation: 2y+kx=5.

Answer 1

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Answer 2

Answer:

$k=-7/5$

Step-by-step explanation:

you have the point $A(5,6)$

from this point we know that: $x=5$ and $y=6$

so we must substitute this into the equation $2y+kx=5$, and this is how we will find which value of k makes true that the point (5,6) belongs to the graph.

So substituting $x=5$ and $y=6$:

$2y+kx=5\\2(6)+k(5)=5\\12+5k=5$

and we clear for the variable k:

$5k=5-12\\5k=-7$

and thus, k is:

$k=-7/5$

the value for k must be -7/5.