Question

Which function has a range of y<3?
y=3(2)
y=2(3)*
y=-(2)* + 3
y= (2)X-3

Answer 1

The function that has a range of y<3 is y=-(2)* + 3

Answer: Option(c)

Step-by-step explanation:

Solution:

Lets shall evaluate the options given in the question

In Option 1; y=3(2) that is

$y=3 \times 2=6$

So the value of y>3 and thus option 1 fails

In option 2; y=2(3)*

This expression indicates that the power of 3 all result in positive values and sometimes zero such that for $2 \times 3^{0}=0$ and for values other than one y will be greater than 3. so option 2 fails.

In option 4; y=2x(-3)

On solving we get $y=2 \times(-3)=-6$

Though it is less than 3 but it has an negative value. So option 4 fails.

In option 3; y=-(2)* + 3

This option indicates for all power values of -2 the y value will be less than 3 such that

For power value 0 we get

$y=-2^{0}+3$

y=0+3=3

And for the power value 1 we get

$y=-2^{1}+3$

y=-2+3=1

So in the both the occasion the value of y<3 than and it is not an negative value and thus option 3 satisfy the functional range y<3.

Result:

Thus the function that has a range of y<3 is y=-(2)* + 3