Question

A rectangle has an area of 40 and a perimeter of 28 what is it’s length

Answer 1

It is 10, because area=length x width and perimeter is 2L + 2W so is we multiply 10 times 4 we get 40 for the area, and if we add all the sides (4+4+10+10) we get 28. So 10 must be the length of the rectangle

Answer 2

The length of the rectangle that has an area of 40 ft² and perimter of 28 ft is: 10 ft.

What is the Area and Perimeter of a Rectangle?

Area of rectangle = length × width

Perimeter of rectangle = 2(length + width).

We are given the following:

Area = 40 ft²

Perimeter = 26 ft

Let x represent a side of the rectangle. Therefore, the other side would be:

(28 - 2x)/2 = 14 - x

Area of rectangle = (14 - x) × x

40 = 14x - x²

x² - 14x + 40 = 0

Factorize

(x - 4)(x - 10) = 0

x = 4 or x = 10.

Therefore, the length of the rectangle would be 10 ft.

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