Question

If the ordinate is three more than twice the abscissa and x {-1, 0, -}, which of the following sets of ordered pairs satisfies the given conditions? {(-1, 1), (0, 3), (-1/3, 7/3)} {(-1, 1), (0, 3), (-1/3, 11/3)} {(-1, -1), (0, 3), (-1/3, 1)}

Answer 1

Answer:

The pairs: (-1, 1), (0, 3), (-1/3, 7/3)

Step-by-step explanation:

The "ordinate" identifies the quantity plotted on the vertical axis (y-variable), while the "abscissa" is the quantity on the horizontal axis (x-variable). Therefore, the words:

"the ordinate is three more than twice the abscissa" translate into:

y = 2 * x + 3

and we use this formula to evaluate what ordered pairs satisfy such formula, using for x-values the three listed numbers: {-1.0. -1/3)

Here the evaluation:

$y=2*x +3\\y=2*(-1)+3 = -2+3=1$ which gives the pair: (-1, 1)

$y=2*x +3\\y=2*(0)+3 = 0+3=3$ which gives the pair: (0,3)

$y=2*x +3\\y=2*(-1/3)+3 = -2/3+3=7/3$ which gives the pair: (-1/3, 7/3)

Answer 2

Answer:

(-1, 1), (0, 3), (-1/3, 7/3)

Step-by-step explanation: