Please please help me out!!!!!!!!!
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Answer:
y = [tex]\frac{3}{4}[/tex] x + [tex]\frac{1}{4}[/tex]
Step-by-step explanation:
The equation of a line in slope- intercept form is
y = mx + c ( m is the slope and c the y- intercept )
Calculate m using the slope formula
m = (y₂ - y₁ ) / (x₂ - x₁ )
with (x₁, y₁ ) = (- 3, - 2) and (x₂, y₂ ) = (5, 4) ← 2 points on the line
m = [tex]\frac{4+2}{5+3}[/tex] = [tex]\frac{6}{8}[/tex] = [tex]\frac{3}{4}[/tex], thus
y = [tex]\frac{3}{4}[/tex] x + c ← is the partial equation of the line
To find c substitute either of the 2 points into the partial equation
Using (5, 4), then
4 = [tex]\frac{15}{4}[/tex] + c ⇒ c = 4 - [tex]\frac{15}{4}[/tex] = [tex]\frac{1}{4}[/tex]
y = [tex]\frac{3}{4}[/tex] x + [tex]\frac{1}{4}[/tex] ← equation of line
Answer:
y = 3/4x + 1/4.
Step-by-step explanation:
The upper dot on the line is the point (5, 4) and the lower one is the point (-3,-2) so the slope of the line is:
(4 - -2) / (5 - -3)
= 6/8
= 3/4.
Using the point slope form of a line with m = 3/4 and (x1,y1) = (5,4)
y - y1 = m(x - x1)
y - 4 = 3/4(x - 5)
y = 3/4x + 1/4