Answer:
ΔH=483 kJ
Explanation:
Its given that
For the reaction A+2B→C+3D has ΔH = 161 kJ.
As the ΔH is positive this is an endothermic reaction where we supply energy.
It is given that we supposed to find ΔH for the following equation.
3A+6B→3C+9D ΔH=?
So we observe that
3*(A+2B)→3*(C+3D)
So the whole reaction is rised with a coefficient of 3 hence the ΔH would be three times the original one.
ΔH=3*161 kJ
ΔH=483 kJ
