Question

Circle C is shown. Line segments E C and C D are radii. Lines are drawn from points E and D to point F on the other side of the circle. Arc E D measures 95 degrees. What is the measure of angle EFD? 37.5° 45° 47.5° 55°

Answer 1

Answer:

$47.5^o$

Step-by-step explanation:

If sketch of the circle and its points is shown as in the accompanying image, notice that the triangle formed FEC is an isosceles triangle, of which we know the angle at the center (angle ECF) to measure $180^o-95^o=85^o$.

Since the other two remaining angles must be equal to each other (they are opposite to sides of the same length - radii CE and CF of the circle), we have that the sum of all must render $180^o$:

$CFE +FEC+85^o=180^o\\2*CFE+85^o=180^o\\2*CFE=180^o-85^o\\2*CFE=95^o\\CFE=\frac{95^o}{2} \\CFE=47.5^o$

Answer 2

Answer:

47.5

Step-by-step explanation:

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