Answer:
Initial speed of the ball, u = 16 m/s
Explanation:
It is given that, a juggler tosses a single ball high in the air. She catches the ball 3.3 s later at the same height from which it was thrown. Let u is the initial upward speed of the ball.
At the highest point, the final speed of the ball, v = 0
Using equation of motion as :
[tex]v=u+at[/tex]
a = -g
[tex]0=u-gt[/tex]
Let [tex]t_a\ and\ t_d[/tex] are time of ascent and descent respectively.
So, total time, [tex]t=\dfrac{2u}{g}[/tex]
[tex]3.3=\dfrac{2u}{9.8}[/tex]
u = 16.17 m/s
or
u = 16 m/s
So, the initial upward speed of the ball is 16 m/s. Hence, this is the required solution.