Answer:4.6 hr
Explanation:
Given
area of divider is 0.25 m^2
conductivity of glass k=0.9 W/m.K
mass of water =30 kg
specific heat c=4180 J/kg.K
initial temperature difference [tex]T_1=20 K[/tex]
Final temperature difference [tex]T_2=1 K[/tex]
Let Temperature difference be T so change in temperature difference is given by dT in time dt
rate of heat flow is [tex]\frac{Q}{t}=\frac{kA dT}{dx}[/tex]
[tex]\frac{Q}{t}=\frac{0.9\times 0.25\times dT}{0.02}[/tex]
[tex]\frac{Q}{t}=11.25dT[/tex]----1
Also heat transferred by water
[tex]dQ=-\frac{mc\Delta T}{2}[/tex]----2
equating 1 & 2
[tex]-\frac{mc\Delta T}{2}=11.25dT[/tex]
[tex]-62700\frac{\mathrm{d} T}{\mathrm{d} T}=11.25dt[/tex]
integrating for T=20 to T=1 for time t
[tex]\left ( -62700\ln T\right )_{20}^1=t[/tex]
t=16696.2 s
t=4.6 hr