A large container is separated into two halves by al= 2.0 cm thick glass divider. The area of the divider is= 0.25 m2and the thermal conductivity of glass isk= 0.90 W/m·K. Each side is filled withm= 30 kg of water, specific heatc= 4180 J/kg·K, at different temperatures. Initially, the temperature difference is ∆T0= 20 K. How long will it take before the temperature difference is ∆T= 1.0 K

Respuesta :

Answer:4.6 hr

Explanation:

Given

area of divider is 0.25 m^2

conductivity of glass k=0.9 W/m.K

mass of water =30 kg

specific heat c=4180 J/kg.K

initial temperature difference [tex]T_1=20 K[/tex]

Final temperature difference [tex]T_2=1 K[/tex]

Let Temperature difference be T so change in temperature difference is given by dT in time dt

rate of heat flow is [tex]\frac{Q}{t}=\frac{kA dT}{dx}[/tex]

[tex]\frac{Q}{t}=\frac{0.9\times 0.25\times dT}{0.02}[/tex]

[tex]\frac{Q}{t}=11.25dT[/tex]----1

Also heat transferred by water

[tex]dQ=-\frac{mc\Delta T}{2}[/tex]----2

equating 1 & 2

[tex]-\frac{mc\Delta T}{2}=11.25dT[/tex]

[tex]-62700\frac{\mathrm{d} T}{\mathrm{d} T}=11.25dt[/tex]

integrating for T=20 to T=1 for time t

[tex]\left ( -62700\ln T\right )_{20}^1=t[/tex]

t=16696.2 s

t=4.6 hr

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