Question

Place the indicated product in the proper location on the grid. Place a 0 before the decimals. (0.1x + 0.4y)2

Answer 1

Answer:

$0.01x^{2} +0.08xy+0.16y^{2}$

Step-by-step explanation:

For the following expression

($(0.1x + 0.4y)^{2}$)}

First, write the multiplication factors:

$(0.1x + 0.4y)(0.1x + 0.4y)$

Then multiply by the first term 0.1x, and later by the second term 0.4y.

You can rewrite the multiplication like this:

$(0.1x + 0.4y)\\(0.1x + 0.4y)$ =

$0.01x^{2} + 0.04xy$

                       $+0.04xy + 0.16y^{2}$

-----> Now add similar terms and you will get:

$0.01x^{2}  + 0.08xy + 0.16y^{2}$