Question

Place the indicated product in the proper location on the grid. (4x^3+7y^3 z^ 4) ^2

Answer 1

Answer:

$16x^{6} +56x^{3}y^{3} z^{4} +49y^{6} z^{8}$

Step-by-step explanation:

To solve this type of problems first need to review some laws of exponents:

When you are multiplying the same base, you need to add the exponents.

$x^{2} +x^{8}  = x^{2+8}  = x^{10}$

When you are raising a base with power to another power, you should keep the base and multiply the exponents:

$(x^{2} y^{5})^3 = x^{2*3} y^{5*3} = x^{6} y^{15}$

Now for the expression $(4x^{3} + 7y^{3} z^{4} )^2$

Write the multiplying factors:

$(4x^{3} + 7y^{3} z^{4} )(4x^{3} + 7y^{3} z^{4} )$

Multiply the term $4x^{3}$

$(4x^{3} + 7y^{3} z^{4} )(4x^{3} + 7y^{3} z^{4} ) = 16x^{3+3} + 28x^3y^{3} z^{4}$

Then multiply the term $7y^{3}z^{4}$

$(4x^{3} + 7y^{3} z^{4} )(4x^{3} + 7y^{3} z^{4} ) = 16x^{3+3} + 28x^3y^{3} z^{4}\\\\+ 28x^3y^{3} z^{4} + 49y^{3+3} z^{4+4}$

Simplify the exponents:

$(4x^{3} + 7y^{3} z^{4} )(4x^{3} + 7y^{3} z^{4} ) = 16x^{6} + 28x^3y^{3} z^{4}\\\\+ 28x^3y^{3} z^{4} + 49y^{6} z^{8}$

Add like terms:

$= 16x^{6} + 56x^3y^{3} z^{4} + 49y^{6} z^{8}$