Answer:
[tex]v=25.46m/s[/tex]
Explanation:
The equation for centripetal acceleration of an object that moves in a circle of radius r at velocity v is:
[tex]a_{cp}=\frac{v^2}{r}[/tex]
So we can write this velocity as [tex]v=\sqrt{a_{cp}r}[/tex]
Our chamber is r=14m from the center of the trajectory, and we want our centripetal acceleration to be 4.72g, where g is [tex]9.81m/s^2[/tex], so with these values we have:
[tex]v=\sqrt{4.72gr}=\sqrt{4.72(9.81m/s^2)(14m)}=25.46m/s[/tex]