Question

Find the quotient and the remainder of 11010111 ÷ 1010, assuming that the binary numbers are signed integers in two's complement form.

Answer 1

Answer:

Answered

Explanation:

$(11010111)_2= -32+8+2+1$ = -21

value of 21 = $(010101)_2$

$(100111)_2$= -32+4+2+1= -24

value of 25 = (011001)_2

$-21\times -25 = 525$

$525 = (001000001101)_2$