Question

A rocket accelerates at a rate of 16.4m/s^2 for a distance of 50m. What is the speed at the
end of the 50m? (show work)​

Answer 1

Answer:

40.5 m/s

Explanation:

Given:

v₀ = 0 m/s

a = 16.4 m/s²

Δx = 50 m

Find: v

v² = v₀² + 2aΔx

v² = (0 m/s)² + 2 (16.4 m/s²) (50 m)

v = 40.5 m/s