Question

Determine the equations of the asymptotes: g(x)= $\frac{2x^2+1}{x+3}$

Answer 1

Answer:

• x = -3
• y = 2x -6

Step-by-step explanation:

The vertical asymptote is found where the denominator is zero, at x = -3.

The slant asymptote is the quotient of the division: 2x -6.

  g(x) = (2x^2+1)/(x +3)

  g(x) = 2x -6 +19/(x+3)