Answer:
7. 0.333
8. 29,400 N
9. 91,800 m³
10. 0.84 N
Explanation:
7. Friction force = normal force × coefficient of friction
F = Nμ
(50 N) = (150 N) μ
μ = 0.333
8. Buoyant force = weight of displaced fluid.
B = ρVg
B = (1000 kg/m³) (3 m³) (9.8 m/s²)
B = 29,400 N
9. For an object to float, buoyant force = weight of object.
B = W
ρVg = mg
ρV = m
V = m / ρ
V = (91,800,000 kg) / (1000 kg/m³)
V = 91,800 m³
10. Apply Newton's second law:
∑F = ma
F − W = ma
F − mg = ma
F = mg + ma
F = m (g + a)
F = (0.050 kg) (9.8 m/s² + 7 m/s²)
F = 0.84 N
