Question

Henri has $24,000 invested in stocks and bonds. The amount in stocks is $6,000 more than three times the amount in bonds. Call the amount that Henri invested in stocks s and the amount he invested in bonds b.

Answer 1

Answer:

The solve of that problem is that Hernry invested $18.000 in stocks and $6.000 in bonds.

Step-by-step explanation:

First, to explain you have to do a multiplication about 6 on three. Like three times more than bonds, the result is 18. Then you have to do a  subtraction on $24.000 less $18.000, and the result is $6.000, so six is the amount on bonds. And is three times less than stocks, like the questions ask.

Answer 2

Answer:

Bonds: $4,500

Stocks: $19,500

Step-by-step explanation:

In order to solve this you just need to create a litte equation, to represent the bonds we will use "x" so Bonds equals "x" and the stocks are three times the amount of bonds plus 6,000 that is 3x+6,000, if you add both the result will be $24,000

So the equation would be:

$x+ (3x+6,000)=24,000\\4x+6,000=24,000\\4x=24,000-6,000\\4x=18,000\\x=4,500$