A 59.7 kg sled sits on an incline (without moving) and the angle with respect to the horizontal is θ = 24 degrees. The y component of the weight of the sled, Wy, is : A) 585.657N;
B) 260.751N;
C) 238.208N;
D) 535.024N;

Hello! The most important thing to solve this exercise is to make a good free body diagram of the sled on the hill, our coordinate system is aligned with the slope while the direction of the weight force will always go down, then divide the weight vector into components and we found Wy, I attached the drawing!

Wy=mgcos24

Wy=(59.7)(9.81)(cos24)=535.024N

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A 59.7 kg sled sits on an incline (without moving) and the angle with respect to the horizontal is θ = 24 degrees. The y component of the weight of the sled, Wy, is : A) 585.657N; B) 260.751N; C) 238.208N; D) 535.024N;

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A 59.7 kg sled sits on an incline (without moving) and the angle with respect to the horizontal is θ = 24 degrees. The y component of the weight of the sled, Wy, is : A) 585.657N;
B) 260.751N;
C) 238.208N;
D) 535.024N;