Question

A powerful motorcycle can accelerate from rest to 26.8 m/s (60 mi/h) in only 3.90 s. (a) What is its average acceleration in m/s^2? __________ m/s^2 (b) How far does it travel in that time? __________ m

Answer 1

Answer

given,

v = 26.8 m/s

t = 3.90 s

$a_{avg}=\dfrac{v-u}{t}$

$a_{avg}=\dfrac{26.8-0}{3.9}$

$a_{avg}=6.87\ m/s^2$

average acceleration is equal to $a_{avg}=6.87\ m/s^2$

v² = u² + 2 a s

$26.8^2= 0^2 + 2\times 9.8 \times s$

$s = \dfrac{26.8^2}{2\times 9.8}$

s = 36.64 m

distance travel at that time, s = 36.64 m