Question

A volleyball is hit straight up in
the air with a vertical speed of
7.35 m/s. What is the vertical
displacement of the ball 1.50
seconds after being hit?
a. O m
b. 8.27 m
c. 11.0 m
d. 22.1 m​

Answer 1

Answer:

a. 0 m

Explanation:

Given:

v₀ = 7.35 m/s

a = -9.8 m/s²

t = 1.50 s

Find: Δx

Δx = v₀ t + ½ at²

Δx = (7.35 m/s) (1.50 s) + ½ (-9.8 m/s²) (1.50 s)²

Δx = 0 m