Answer: [tex](17.06\ , 22.94)[/tex]
Step-by-step explanation:
Given : Sample size : n = 16
[tex]\overline{x}=20[/tex]
[tex]s= 6[/tex]
Significance level : [tex]\alpha= 0.05[/tex]
Critical t-value : [tex]z_{\alpha/2}=z_{0.025}=1.96[/tex]
Formula to find the confidence interval for population mean :-
[tex]\overline{x}\pm z_{ \alpha/2}\dfrac{s}{\sqrt{n}}\\\\=20\pm (1.96)\dfrac{6}{\sqrt{16}}\\\\=20\pm2.94=(20-2.94,\ 20+2.94)\\\\=(17.06\ , 22.94)[/tex]
Hence, the 95% confidence interval for the average time required to complete the certification = [tex](17.06\ , 22.94)[/tex]