Question

_____ 10. How many milligrams of active ingredient are required to prepare 10 mL of 0.3% (w/v) solution?

Answer 1

Answer:

30 mg of active ingredient is required to prepare a 0.3% (W/V) solution.

Step-by-step explanation:

0.3% (w/v) solution can also be expressed as: 0.3 g active ingredient for 100 ml of solution.

So:

$\frac{0.3g}{100 ml} *\frac{1000mg}{1g}*10ml$= 30 mg

In conclusion, we need to weigh 30 mg of active ingredient and then dilute it in 10 ml of water.