Question

After an object moves for 15.0 s, it's x displacement is 27.5 m. After moving for a total of 35.0 s, the x displacement of the same object is 42.5 m. What is the average velocity of an object in the X direction during the period of time between 15.0 and 35.0

Answer 1

Answer:

Average velocity $v_{p} = 1.515 \frac{m}{s}$

Step-by-step explanation:

The information during the motion

$t_{1}=15 s$

$t_{2}=35 s$

$x_{1}=27.5 m$

$x_{2}=42.5 m$

So the velocity in each motion is:

$v_{1}=\frac{x_{1} }{t_{1}}\\ v_{1}=\frac{27.5m }{15 s}\\v_{1}=1.83 \frac{m}{s}$

$v_{2}=\frac{x_{2} }{t_{2}}\\ v_{2}=\frac{42.5 m }{35 s}\\v_{1}=1.2 \frac{m}{s}$

Velocity average:

$v_{p}=\frac{v_{1}+v_{2}}{2} = \frac{1.83\frac{m}{s}+ 1.2\frac{m}{s}}{2}  \\v_{p}= \frac{3.03(\frac{m}{s} )}{2} \\v_{p}= 1.515 \frac{m}{s}$