Question

the perimeter of a rectangle is twice the sum of its length and its width. the perimeter is 46 meters and its length is 2 meters more than twice its width

Answer 1

Answer:

The length of rectangle is 16 meters and the width of rectangle is 7 meters

Step-by-step explanation:

Let

L -----> the length of the rectangle

W ---> the width of the rectangle

we know that

The perimeter of rectangle is equal to

$P=2(L+W)$ ----> the perimeter of a rectangle is twice the sum of its length and its width

we have

$P=46\ m$

so

$46=2(L+W)$

simplify

$23=(L+W)$ -----> equation A

$L=2W+2$ ----> equation B

substitute equation B in equation A and solve for W

$23=(2W+2+W)$

$23=3W+2$

$3W=23-2$

$3W=21$

$W=7\ m$

Find the value of L

$L=2(7)+2=16\ m$

therefore

The length of rectangle is 16 meters and the width of rectangle is 7 meters