The temperature of the body is equal to 39.48°C
Why?
To find the temperature of the body that produces 9.0cm of this mercury column, we need to use the formula for linear interpolation. Also, the temperatures to use are based on the Celsius degrees scale.
For the fixed tempetatures, we have:
[tex]1.26cm=0\°C(ColdWaterPoint)\\20.86cm=100\°C(BoilingWater)Point\\[/tex]
So, we know that:
We will need to use the following formula to linear interpolation:
[tex]y=\frac{x-x_{1}}{x_{2}-x_{1}}*(y_{2}-y_{1})+y_{1}[/tex]
Then, we have:
[tex]1.26cm=0\°C\\20.86cm=100\°C\\9.0cm=???\\\\x_{1}=1.26cm,y_{1}=0\°C\\\\x_{2}=20.86cm,y_{2}=100\°C\\\\x=9.0cm,y=???[/tex]
So, interpolating we have:
[tex]y=\frac{(9cm-1.26cm)}{(20.86cm-1.26cm)}*(100\°C -0\°C)+0\°C\\\\y=0.39*100\°C=39.48100\°C[/tex]
Hence, the temperature of the body is equal to 39.48°C
Have a nice day!