Answer:
The slope of a line that contains the points (0, -2), (3, 1) is 1 and points (0.-2), (2.-8) is -3
Solution:
2. For the first problem,
The points are [tex](x_1,y_1) = (0,-2)[/tex] and[tex](x_2,y_2) = (3,1)[/tex]
Let us assume that the slope is m.
We know the slope on a point [tex]=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}[/tex]
Now substituting the value of the points we get,
[tex]\text { Slope } m=\frac{1-(-2)}{3-0}=\frac{1+2}{3}=\frac{3}{3}=1[/tex]
3. For the second problem,
The points are [tex](x_1,y_1) = (0,-2)[/tex] and [tex](x_2,y_2) = (2,-8)[/tex]
Let us assume that the slope is m1
We know the slope on a point [tex]=\frac{y_{2}-y_{1}}{x_{2}-x_1}[/tex]
Now putting the value of the points we get,
[tex]\text { Slope } m 1=\frac{-8-(-2)}{2-0}=\frac{-6}{2}=(-3)[/tex]
