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You push a ball with a net force of 2 N and it accelerates. What happens if you exert 2 N of net force on an object that has 3 times the mass?
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1. The object will accelerate the same amount as before because the mass does not affect the object’s acceleration.

2. The object will accelerate 1/3 as much because if you apply the same net force but increase the mass, the acceleration will decrease.

3. The object will not accelerate because now it is too heavy.

4. The object will accelerate 3 times as much because if you apply the same net force and increase the mass, the acceleration will increase.

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Answer:

The answer to your question is: number 2 is correct.

Explanation:

Formula

                     F   =  m  x  a

                     [tex]a = \frac{F}{m}[/tex]

The formula shows that acceleration and mass and inversely proportional, then if the mass increases 3 times, then the acceleration must diminishes 3 times.

1. The object will accelerate the same amount as before because the mass does not affect the object’s acceleration. This option is incorrect, the acceleration must diminish.

2. The object will accelerate 1/3 as much because if you apply the same net force but increase the mass, the acceleration will decrease.  This option is correct, is what i describe above.

3. The object will not accelerate because now it is too heavy. this option is wrong, because the object will accelerate.

4. The object will accelerate 3 times as much because if you apply the same net force and increase the mass, the acceleration will increase. This option s incorrect, the acceleration will diminish not increase.

Answer:

2.  The object will accelerate 1/3 as much because if you apply the same net force but increase the mass, the acceleration will decrease.

Explanation:

This is an example of Newton's Second Law of motion.

Force = mass * acceleration (a).

So if the  mass is m and the force is 2:

2 = m * a  So a = 2/m

If the mass is increased  to 3m then

2 = 3m * a2   where a2 is the new acceleration, so  

a2 = 2/3m.

Comparing the 2 accelerations:

= 2/3m / 2/m

= 2/3m * m /2

= 2/6

= 1/3 of the previous acceleration.

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