Answer:
There is a 20% probability that the store selected does not violate the institute scanner accuracy standard
Step-by-step explanation:
70 company stores were investigared.
56 violated the institute's scanner accuracy standard.
70-56 = 14 did not violate the institute scanner accuracy standard.
If 1 of the 70 company stores is randomly selected, what is the probability that that store does not violate the institute scanner accuracy standard?
This is 14 divided by 70, so:
[tex]P = \frac{14}{70} = 0.2[/tex]
There is a 20% probability that the store selected does not violate the institute scanner accuracy standard