Question

You have a balloon that is inflated to 105kpa, with a volume of 2.2L, at a temperature of 295k. When you step outside into the cold winter weather, the balloon's temperature decreases to 279k. What is the volume, in liters, of the balloon while you are standing?

Answer 1

Answer:

The law of gases volumen

v= 2.08 L

Explanation:

Using equations of gas:

$\frac{P_{1} *v_{1}  }{T_{1} }= \frac{P_{2} *v_{2}  }{T_{2} }$

P1= 105 kpa is constant because the ballon continue

$\frac{v_{1} }{T_{1}}= \frac{v_{2} }{T_{2}}\\v_{2}= \frac{v_{1}*T_{2} }{T_{1}}\\v_{2}= \frac{2.2 L*279 k }{295 k}\\v_{2}= \frac{613.8 L* k }{295 k}\\v_{2}= 2.08 \frac{ L* k }{ k}\\v_{2}= 2.08 L$

So the volumen while is outside in liters is v= 2.08