Answer:
Quadratic equation with roots 1/3 and -7/2 is:
[tex]6x^{2} + 19x - 7 = 0[/tex]
Step-by-step explanation:
Roots of the equation are 1/3 and -7/2
Quadratic equation is of the form:
[tex]ax^{2} +bx + c = o[/tex]
Now Sum of roots = [tex]\frac{-b}{a}[/tex]
Sum of roots = [tex]\frac{1}{3} + (\frac{-7}{2}) = \frac{2 - 21}{6} = \frac{- 19}{6} = \frac{- b}{a}[/tex]
∴ b = 19 and a = 6
Product of roots = c/a
Product of the roots = [tex]\frac{1}{3} \times \frac{-7}{2} = \frac{-7}{6} = \frac{c}{a}[/tex]
∴ a = 6, b = 19 and c = -7
So the quadratic equation with roots 1/3 and -7/2 is:
[tex]6x^{2} + 19x - 7 = 0[/tex]
Answer:
The answer would be, Y= (3x - 1) (2x + 7)
Step-by-step explanation:
