Respuesta :
Answer: 15,22 and 66
Step-by-step explanation: Call the numbers a,b and c.
Their sum is 103 so a+b+c=103
The second number is 7 more than the first so b=a+7
The third number = 3 times the second so c=3b
Now replace c with 3b in the top equation, so a+b+3b=103, which becomes a+4b=103
Now replace b with a+7, so a+4(a+7)=103. This solves to give a=15
b=a+7 so b=22 and c=3b so c=66
The numbers are 15,22, 66 if the second number is 7 more than the first and the third number is 3 times the second.
What is sum?
Sum of any numbers is the summation of any set of numbers. It is the total of all numbers.
How to calculate the numbers?
let the first number be x
According to question
second number = x+7
third number=3(x+7)
x+x+7+3(x+7)=103
x+x+7+3x+21=103
5x+28=103
5x=75
x=15
First number=15
Second number=15+7=22
Third number=3(15+7)=66
Hence the numbers be 15,22,66.
Learn more about sum at https://brainly.com/question/542712
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