Respuesta :

Answer:

[tex]14 = a[/tex]

Step-by-step explanation:

___

SQ is a segment bisector RQS and ∠PQS, so set both expressions equal to each other:

a + 28 = 3a

-a - a

_________

28 = 2a

__ __

2 2

[tex]14 = a[/tex]

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