The evil team of Ms. Moonstruck and Mr. Luny intend to deflect the Moon from its orbit around Earth by pulling it with a force of 3370 N . They plan to accomplish this by placing a mini black hole 6.83×106 m from the center of the Moon and letting gravitation do what gravitation does. What must the mass of the mini black hole be for the evil duo's evil scheme to succeed? The mass of the Moon is 7.36×1022 kg .

To solve this problem you should know Isaac Newton found an equation that determines the force of attraction between two bodies with mass acting in a gravitational field, at a distance r, the equation is as follows

[tex]F=G\frac{ m1 m2}{r^2}[/tex]

where

G = It is the unirvesal gravitational constant= 6.67x10^-11 Nm^2/kg^2

m1=mass of the moon=7.36×10^22 kg

m2= mass of the mini black hole

r=distance=6.83×10^6 m

F=force=3370N

solving for m

[tex]\frac{(F)(r^2)}{m1(G)} =m2[/tex]

[tex]\frac{(3370)((6.83X10^6)^2)}{(7.36X10^22)(6.67x10^-11)} =m2[/tex]

m2=32023kg

okpalawalter8 okpalawalter8 · Answer 2 · 2022-04-12T13:47:08+02:00

The mass of the mini black hole be for the evil duo's evil scheme to succeed is mathematically given as

m2=32023kg

What must the mass of the mini black hole be for the evil duo's evil scheme to succeed?

Question Parameter(s):

Generally, the equation for the Frequency is mathematically given as

[tex]F=G\frac{ m1 m2}{r^2}[/tex]

Therefore

[tex]m2=\frac{(F)(r^2)}{m1(G)}[/tex]

[tex]m2=\frac{(3370)((6.83*10^6)^2)}{(7.36*10^22)(6.67*10^-11)}[/tex]

m2=32023kg

In conclusion, The mass is

m2=32023kg