Answer:
550.66 gallons
Step-by-step explanation:
Given:
Farm product contains 12.5% w/v concentrate of tiamulin hydrogen fumarate
i.e
100 mL of solution of farm product contains 12.5 g of tiamulin hydrogen fumarate
Thus,
by unitary method
1 mL of solution contains [tex]\frac{\textup{12.5 g}}{\textup{100}}[/tex] of tiamulin hydrogen fumarate
therefore,
1 L i.e 1000 mL of solution contains [tex]\frac{\textup{12.5 g}}{\textup{100}}\times1000[/tex] of tiamulin hydrogen fumarate
or
1 L i.e 1000 mL of solution contains 125 g of tiamulin hydrogen fumarat
also, final product contains 227 mg of tiamulin hydrogen fumarate per gallon
therefore,
The number of gallons of medicated water that can be prepared
= [tex]\frac{\textup{weight of concentrate in a litre}}{\textup{ tiamulin hydrogen fumarate per gallon}}[/tex]
= [tex]\frac{\textup{125 g}}{\textup{227 mg/gallon}}[/tex]
= [tex]\frac{\textup{125}\times1000\textup{mg}}{\textup{227 mg/gallon}}[/tex]
= 550.66 gallons