Respuesta :
Answer: 0.55m
1. First find Vf
• 4 Sin(10)=0.7
•Vf= 0.7
2. Find time
•9.8=0.7/t
•9.8t=0.7
•t=0.07
3. Find distance
• 4 Cos(10)=d/0.14 < ————- double time
• d=0.55m
1. First find Vf
• 4 Sin(10)=0.7
•Vf= 0.7
2. Find time
•9.8=0.7/t
•9.8t=0.7
•t=0.07
3. Find distance
• 4 Cos(10)=d/0.14 < ————- double time
• d=0.55m
Answer:
The ball goes 0.555 meter far away when kicked with a speed of 4 m/s at an angle of 10ﾟ.
Explanation :
From the given statements, we know
Initial Velocity (u) = 4 m/s
Angle at which it is projected (θ) = 10 degree
Let acceleration due to gravity (g) = 9.8 m/[tex]s^2[/tex]
Range = ?
Using the formula of Range, and substituting the values
Range= [tex]\frac{\mathrm{u}^{2} \sin 2 \theta}{\mathrm{g}}[/tex]
= [tex]\frac{4^{2} \sin 2 \times 10}{9.8}[/tex]
= [tex]\frac{16 \times 0.34}{9.8}[/tex] = 0.555 m
