Answer:
The hydrostatic force of 313920 N is acted on each wall of the swimming pool and this force is acted at 1 m from the ground. The hydrostatic force is quadruple if the height of the walls is doubled.
Explanation:
To calculate force on the walls of swimming pool whose dimensions are given as 8-m-long, 8-m-wide, and 2-m-high. We know that formula for hydrostatic force is [tex]\text {hydrostatic force}=\text {pressure} \times \text {area,}=\rho g h \times(l \times h)[/tex]
[tex]\equiv \rho g h^{2} l[/tex], we know ρ=density of fluid=1000 [tex]g / c m^{3}[/tex],
g=acceleration due to gravity=9.81 [tex]m / s^{2}[/tex], h=height of the pool=2 m and l=length of the pool=8 m.
hydrostatic force on each wall=[tex]1000 \times 9.81 \times 2^{2} \times 8[/tex] = 313920 N.
The distance at which hydrostatic force is acted is half of the height of the swimming pool.
At 1 m from the ground this hydrostatic force is acted on each wall.
The force is quadruple if the height of the walls of the pool is doubled this is because, the height is doubled and taken as h=4 m and substitute in the equation =[tex]\rho g h^{2} l[/tex] = [tex]1000 \times 9.81 \times 4^{2} \times 8[/tex] = 1255680 N. This is 4 times 313920 N.
