Answer: a) 4.32 MJ ; b) 0.32%
Explanation: In order to solve this question we have to consider that power consume to full charge the battery is I*V
so we have 100 A-hours* 12 V = 1200 W*hours ( J*hour/s)
To convert to Joules
we have to multiply by 3600 ( seconds per hour) the Total energy stored in the battery is:
E= 1200 J/s* 3600 s= 4.32 MJ
To compare with the energy of 9 gallon petrol tank ( 1350 MJ)
%= E electric/ Epetrol= (4.32 MJ/(1350 MJ))*100%=0.32 %