Question

Find the equation of a line passing through (-4,3) and (1,2)

Answer 1

Answer:

The answer to your question is:  

slope y-intercept      ( y - 2) = -1/5 (x - 1)

general equation       x + 5y - 11 = 0

Step-by-step explanation:

Data

A (-4, 3)

B (1, 2)

slope = m = $\frac{(y2- y1)}{(x2 - x1)}$

Process

                m = $\frac{(2 - 3)}{(1 + 4)}$

                m = $\frac{-1}{5}$

               (y - y1) = m(x - x1)

               ( y - 2) = -1/5(x - 1)

              5(y - 2) = -1(x - 1)

              5y - 10 = -x + 1

              x + 5y - 11 = 0