Answer:
The electrical flow through the borehole is 353 Nm²/C.
(e) is correct option.
Explanation:
Given that,
Radius = 8.00 cm
Charge = 20.00 μC
radius of drill = 2.00 mm
We need to calculate the electrical flow through the borehole
Using formula of electric flow
[tex]\phi=EA[/tex]
[tex]\phi=\dfrac{kq}{R^2}\times\pi\times r^2[/tex]
Where, q = charge
R = radius of sphere
r = radius of drill
Put the value into the formula
[tex]\phi=\dfrac{9\times10^{9}\times20\times10^{-6}}{(8\times10^{-2})^2}\times\pi\times(2.00\times10^{-3})^2[/tex]
[tex]\phi=353\ Nm^2/C[/tex]
Hence, The electrical flow through the borehole is 353 Nm²/C.