Answer:
-63.98° C
Explanation:
Initial diameter of rivet d = 1.873 cm
Hole diameter d ' = 1.871 cm
Coefficient of linear expansion of steel α = 12×10 -6 /° C
Initial temperature t = 25° C
We know α = ( d' - d ) / [ d ( t ' - t ) ]
t ' - t = ( d ' - d ) / [ d x α ]
putting values we get
t ' - t = -88.98° C
t ' = -88.98° C + t
= -63.98° C
The temperature must the rivet be cooled if it is to fit in the hole (at 25°C) is -63.98° C