Answer:
Step-by-step explanation:
The slope-intercept form of an equation of a line:
[tex]y=mx+b[/tex]
m - slope
b - y-intercept
We have
[tex]m=\dfrac{2}{3},\ (0,\ -3)\ro b=-3[/tex]
Substitute:
[tex]y=\dfrac{2}{3}x-3[/tex]
Convert to the standard form (Ax + By = C):
[tex]y=\dfrac{2}{3}x-3[/tex] multiply both sides by 3
[tex]3y=3\!\!\!\!\diagup\cdot\dfrac{2}{3\!\!\!\!\diagup}x-(3)(3)[/tex]
[tex]3y=2x-9[/tex] subtract 2x from both sides
[tex]-2x+3y=-9[/tex] change the signs
[tex]2x-3y=9[/tex]