Question

A jet fighter plane is launched from a catapult on an airaraft carrier. It reaches a speed of 42 mis at the end of the catapult, and this requires 2.0s. Assuming the acceleration is O 63 m O 24 m O 84 m O 42 m O 16 m

Answer 1

Answer:

s = 42 meters                            

Explanation:

Initial speed of the jet, u = 0

Final speed of the jet, v = 42 m/s

Time taken, t = 2 s

Let a is the acceleration of the jet. It can be calculated using equation of kinematics as :

$a=\dfrac{v-u}{t}$

$a=\dfrac{42\ m/s}{2\ s}$    

$a=21\ m/s^2$

It is assumed that the acceleration of the jet is constant. We can find the length of the catapult. It is given by s.  

$s=ut+\dfrac{1}{2}at^2$

$s=\dfrac{1}{2}\times 21\times (2)^2$    

s = 42 meters

So, the length of the catapult is 42 meters. Hence, this is the required solution.