Answer : The correct option is (d) 2.73 m
Explanation :
By the 2nd equation of motion,
[tex]s=ut+\frac{1}{2}at^2[/tex]
where,
s = distance or height = ?
u = initial velocity = 3.0 m/s
t = time = 0.5 s
a = acceleration due to gravity = [tex]9.8m/s^2[/tex]
Now put all the given values in the above equation, we get:
[tex]s=(3.0m/s)\times (0.5s)+\frac{1}{2}\times (9.8m/s^2)\times (0.5s)^2[/tex]
[tex]s=2.73m[/tex]
Therefore, the correct option is (d) 2.73 m