Question

Aluminum had a specific heat of 0.215 cal/(g °C). When 25.7 cal (108.5 J) of heat is added to 18.4 g of aluminum at 20.0°C, what is the final temperature of the aluminum?

Answer 1

Answer:

26.5°C

Explanation:

Heat added is the product of mass, specific heat capacity, and change in temperature.

q = mC(T − T₀)

25.7 cal = (18.4 g) (0.215 cal/g/°C) (T − 20.0°C)

T = 26.5°C